Odpowiedź:
Zadanie 4
a) 4(3a + 5) + (5a - 2) = 12a + 20 + 15a - 6 = 27a + 14
b) 2(7p - 3) - 5(3p - 1) = 14p - 6 - 15p + 5 = - p - 1
c) - 5(2 - 3m) - 2(m + 8) = -10 + 15m - 2m - 16 = - 26 + 13m
d) 2x(3x - 4) + x(5 - 2x) = 6x² - 8x + 5x - 2x² = 4x² - 10x
e) 3u(2 - 4u) - 5u(u + 3) = 6u - 12u² - 5u² - 3u = 3u - 17u²
f) - 5t (2t - 1) - 2t(3 - 5t) = -10t² + 5t - 6t + 10t² = -t
Zadanie 5
a) 2(3p - 4) +[tex]\frac{4-2p}{2}[/tex] = 6p - 8 +[tex]\frac{4-2p}{2}[/tex]= 6p - 8 + [tex]\frac{4}{2}[/tex] - [tex]\frac{2}{2}[/tex] = 6p - 8 + 2 - p = 5p - 6
b) 3(2 - 5m) - [tex]\frac{12m+9}{3}[/tex] = 6 - 15m - [tex]\frac{12}{3}[/tex] + [tex]\frac{9}{3}[/tex] = 6 - 15m - 4m - 3 = 3 - 19m
c) -5(4t - 2) - [tex]\frac{30t-5}{5}[/tex] = -20t + 10 -([tex]\frac{30t}{5}[/tex] - [tex]\frac{5}{5}[/tex]) = -20t + 10 - 6t + 1 - 26t + 11
d) [tex]\frac{6x-14}{2}[/tex] + [tex]\frac{6+15x}{3}[/tex] = [tex]\frac{6x}{2}[/tex] - [tex]\frac{14}{2}[/tex] + [tex]\frac{6}{3}[/tex] + [tex]\frac{15x}{3}[/tex] = 3x - 7 + 2 + 5x = 8x - 5
e) [tex]\frac{12-20y}{-4}[/tex] + [tex]\frac{14-7y}{7}[/tex] = [tex]\frac{12}{-4}[/tex] - [tex]\frac{20y}{-4}[/tex] + [tex]\frac{14}{7}[/tex] - [tex]\frac{7y}{7}[/tex] = - 3 + 5y + 2 - y = -1 + 4y
Szczegółowe wyjaśnienie:
(Mam nadzieję, że pomogłam)
