Odpowiedź:
z2
a 16
b 30
c 42
z3
a >
b >
c =
d >
z4
a 2 5/7
b 5 3/9
c 6
z5
a 31/4
b 18/7
c 52/2
z6
[tex](3 \frac{9}{20} - 1 \frac{12}{20} ) + (6 \frac{3}{20} - 1 \frac{7}{20} ) = 1 \frac{17}{20} + 4 \frac{16}{20} = 5 \frac{33}{20} = 6 \frac{13}{20} [/tex]
