Odpowiedź:
[tex] {x}^{2} + \sqrt{7} ^{2} = {4}^{2} \\ {x}^{2} + 7 = 16 \\ {x}^{2} = 9 \\ x = 3[/tex]
[tex] {x}^{2} + \sqrt{17} ^{2} = {(7 \sqrt{2} )}^{2} \\ {x}^{2} + 17 = 98 \\ {x}^{2} = 81 \\ x = 9[/tex]
[tex] \frac{y}{2} = 2 \sqrt{3} | \times 2 \\ y = 4 \sqrt{3} \\ x = \frac{4 \sqrt{3} \times \sqrt{3} }{2} = \frac{12}{2} = 6[/tex]
[tex]x = 9 \sqrt{2} \\ {y}^{2} = (9 \sqrt{2} )^{2} + {(9 \sqrt{2} )}^{2} \\ {y}^{2} = 162 + 162 \\ {y}^{2} = 324 \\ y = 18[/tex]
[tex]x \sqrt{2} = 14 \sqrt{2} \\ x = 14 \\ y = 14[/tex]
[tex] {x}^{2} = (4 - \sqrt{5} ) ^{2} + (4 + \sqrt{5} ) {}^{2} \\ {x}^{2} = 11 + 21 \\ {x}^{2} = 32 \\ x = \sqrt{32} \\ x = \sqrt{16 \times 2} \\ x = 4 \sqrt{2} [/tex]
[tex]2y = 8 \\ y = 4 \\ x = 4 \sqrt{3} [/tex]
