Odpowiedź:
[tex]a = {2}^{9} \times 2 = {2}^{10} \\ b = {2}^{7} \div {2}^{2} = {2}^{5} \\ c = {2}^{4} \times 16 = {2}^{4} \times {2}^{4} = {2}^{8} \\ \frac{a + b}{c} = \frac{ {2}^{10} + {2}^{5} }{ {2}^{8} } = {2}^{10 - 8} + {2}^{5 - 8} = {2}^{2} + {2}^{ - 3} = 4 + ( \frac{1}{2} )^{3} = 4 + \frac{1}{8} = 4 \frac{1}{8} [/tex]
