Odpowiedź:
Zadanie 3.1
a) Masa molowa węgla pierwiastkowego = 12g/mol
2mole * 12g/mol = 24g
b) masa molowa CaCO₃ = 40g/mol + 12g/mol + 16g/mol*3 = 52g/mol + 48g/mol = 100g/mol
12 moli * 100g/mol = 1200g
c) masa molowa HNO₃ = 1g/mol + 14g/mol + 48g/mol = 63 g/mol
0,2 mola * 63g/mol = 12,6g
Zadanie 3.2
a) 20g tlenku węgla (IV)
Mco₂ = 2*16g/mol + 12g/mol = 44 g/mol
44g ----- 1 mol
20g ----- x
x=(20g*1 mol)/44g x=5/11 mola ≈0,45 mola
b) 14g pierwiastkowej siarki
Ms = 32 g/mol
32g ----- 1mol
14g ----- x
x=14g*1mol/32g = 14/32 mola =0,4375 mola ≈0,44 mola
c) 0,03g srebra
M Ag= 108 g/mol
108g --- 1 mol
0,03g --- x
x= 0,03g*1mol/108g=0,0002777... mola ≈ 2,78*10⁻⁴ mola
Zadanie 3.3
KMnO4
mKMnO4=39+55+4*16 = 158 g/mo
1 mol = 158 g/mol
x mol = 8g
x=8/158=0,05
1 mol = 6.02*10²³cz.
0.05 mola = x
x=0.05*6.02*10²³ = 0,301*10²³
Na2CO3
mNa2CO3=23*2+12+16*3=106
1 mol = 106 g/mol
x mol = 5 g
x=5/106=0,047
1mol = 6.02*10²³cz
0.047 = x
x=0.047*6.02*10²³≈0,29*10²³
K3PO4
m=3*39+31+4*16 =212
1 mol =212
x mol = 9
x=9/212=0,042
1 mol= 6.02*10²³
0.042 mola = x
x=0.042*6.02*10²³ ≈0,25*10²³
Zadanie 3.6
a)
1mol K3PO4 ------ 8*6,02*10^23 at.
1mol K3PO4 ------ 48,16*10^23 at.
b)
mK3PO4=212u
212g K3PO4 ----- 8*6,02*10^23 at.
180g K3PO4 ------ x at.
x = 40,89*10^23 at.
