Odpowiedź:
[tex]a)\\a^{2} + b^{2} = c^{2}\\4^{2} + 6^{2} = c^{2}\\16 + 36 = c^{2} \\c^{2} = 52 / \sqrt{} \\c=2\sqrt{13} \\\\b)\\a^{2} + b^{2} = c^{2}\\1^{2} + 6^{2} = c^{2}\\1 + 36 = c^{2} \\c^{2} = 37 / \sqrt{} \\c=\sqrt{37}\\\\c)\\6^{2} + b^{2} = c^{2}\\4^{2} + 6^{2} = c^{2}\\36 + 36 = c^{2} \\c^{2} = 72 / \sqrt{} \\c=6\sqrt{2}[/tex]
Szczegółowe wyjaśnienie:
