Oblicz dlugosc odcinka
a) A (1,9) B (3,14)
b) A (1,0) B (2,10)


Odpowiedź :

[tex]Zadanie\\\\\mid AB\mid=\sqrt{(x_B-x_a)^2+(y_b-y_A)^2}\\\\a)\\\\A(1,9)\ ;\ B(3,14)\\\\ \mid AB\mid=\sqrt{(3-1)^2+(14-9)^2}=\sqrt{2^2+5^2}= \sqrt{4+25} =\sqrt{29}\\\\b)\\\\ A(1,0)\ ;\ B(2,10)\\\\\mid AB\mid=\sqrt{(2-1)^2+(10-0)^2}= \sqrt{1^2+10^2}=\sqrt{1+100} =\sqrt{101}[/tex]