[tex]\frac{x}{\sqrt{32} }+\ \left(\sqrt{2} \right)^{2\ }=\ \frac{x+3^0}{\sqrt{9} }-x\\\\\frac{1}{6}x +2 = \frac{-2}{3} x + \frac{1}{3} \; \; \; \; /+\frac{2}{3}x\\\\\frac{5}{6} x + 2 = \frac{1}{3} \; \; \; \; /-2\\\\\frac{5}{6} x = \frac{-5}{3} \; \; \; \; /\cdot\frac{6}{2} \\\\x = -2[/tex]
