Odpowiedź:
x=-1/3 y=8/3=2 i 2/3
Szczegółowe wyjaśnienie:
[tex]\left \{ {{2x+y=2} \atop {-3x+3y=9}} \right. \\\left \{ {{y=2-2x} \atop {-3x+3y=9}} \right. \\-3x+3(2-2x)=9\\-3x+6-6x=9/-6\\-9x=3 /:(-9)\\\left \{ {{x=-3/9=-1/3} \atop {y = 2-2x=2-2\cdot(-\frac{1}{3})=2+\frac{2}{3}=2\frac{2}{3}}} \right. \\\\\left \{ {{x=-\frac{1}{3}} \atop {y=2\frac{2}{3}} \right.[/tex]
Sprawdzenie:
[tex]\left \{ {{2(-\frac{1}{3})+2\frac{2}{3}=-\frac{2}{3}+2\frac{2}{3}=2} \atop {-3(-\frac{1}{3})+3\cdot2\frac{2}{3}=1+3\cdot\frac{8}{3}=1+8=9}} \right.[/tex]
