pomógłby ktoś z matą? prosze:)

a)
[tex] \frac{ {2}^{5} \times {2}^{3} }{ {2}^{8} } = \frac{ {2}^{8} }{ {2}^{8} } = 1[/tex]
b)
[tex] \frac{ {3}^{4} \times {3}^{3} }{ {3}^{2} \times {3}^{0} } = \frac{ {3}^{7} }{ {3}^{2} } = {3}^{5} = 243[/tex]
c)
[tex] \frac{ {9}^{5} \times {9}^{2} }{9 \times {9}^{4} } = \frac{ {9}^{7} }{ {9}^{5} } = {9}^{2} = 81[/tex]
d)
[tex] \frac{ {5}^{11} }{ {5}^{6} \times {5}^{6} } = \frac{ {5}^{11} }{ {5}^{12} } = \frac{1}{5} [/tex]
Odpowiedź:
a) =[tex]\frac{2^{8} }{2^{8} }[/tex]=1
b)=[tex]\frac{3^{7} }{3^{2} }[/tex]=[tex]3^{5}[/tex]
c)=[tex]\frac{9^{7} }{9^{5} }[/tex]=[tex]9^{2}[/tex]
d)=[tex]\frac{5^{11} }{5^{12} }[/tex]=[tex]\frac{1}{5}[/tex]=[tex]5^{-1[/tex]
Szczegółowe wyjaśnienie: