Odpowiedź:
a)
[tex] = \frac{( {2}^{40}) {}^{3} }{ {2}^{118} } = \frac{ {2}^{120} }{ {2}^{118} } = {2}^{2} = 4[/tex]
b)
[tex] = \frac{ {15}^{30} }{ {10}^{30} } \times \frac{( {2}^{5}) {}^{6} }{ ({3}^{4} ) {}^{7} } = \frac{ {15}^{30} \times {2}^{30} }{ {10}^{30} \times {3}^{28} } = \frac{ {3}^{30} }{ {3}^{28} } = {3}^{2} = 9[/tex]
