POTRZEBUJE NA TERAZ DAJE NAJ!!!

POTRZEBUJE NA TERAZ DAJE NAJ class=

Odpowiedź :

Zadanie 5

a) [tex]-\frac{3}{4} + (-8\frac{5}{8}) + (-6\frac{5}{6}) + (-1\frac{3}{8}) = -\frac{3}{4} - 8\frac{5}{8} - 6\frac{5}{6} - 1\frac{3}{8} = -\frac{3}{4} - 10 - 6\frac{5}{6} =[/tex]

[tex]= -\frac{3}{4} - 10 - \frac{39}{6} = -\frac{3}{4} - 10 - \frac{13}{2} = -\frac{3}{4} - \frac{40}{4} - \frac{26}{4} = -\frac{69}{4} = -17\frac{1}{4}[/tex]

b) [tex]-14\frac{1}{2} + (-7\frac{3}{5}) + 8\frac{1}{5} + (-6,3) = -14\frac{1}{2} - 7\frac{3}{5} + 8\frac{1}{5} - \frac{63}{10} = -14\frac{1}{2} + \frac{3}{5} - \frac{63}{10} =[/tex]

[tex]= -\frac{29}{2} + \frac{3}{5} - \frac{63}{10} = -\frac{145}{10} + \frac{6}{10} - \frac{63}{10} = -\frac{202}{10} = -\frac{101}{5} = -20\frac{1}{5}[/tex]

c) [tex]20 + (-16,3) + 4\frac{1}{3} + (-18\frac{2}{3}) = 20 - \frac{163}{10} + 4\frac{1}{3} - 18\frac{2}{3} = 20 - \frac{163}{10} - 14\frac{1}{3} =[/tex]

[tex]= 20 - \frac{163}{10} - \frac{43}{3} = 20 - \frac{84}{5} - \frac{43}{3} = \frac{300}{15} - \frac{252}{15} - \frac{215}{15} = - \frac{167}{15} = -11\frac{2}{15}[/tex]

d) [tex]-0,6 + 2\frac{3}{8} + (-7\frac{5}{8}) + (-\frac{1}{2}) + 0 = -\frac{3}{5} + 2\frac{3}{8} - 7\frac{5}{8} - \frac{1}{2} = -\frac{3}{5} - \frac{42}{8} - \frac{1}{2} =[/tex]

[tex]-\frac{3}{5} - \frac{21}{4} - \frac{1}{2} = -\frac{12}{20} - \frac{105}{20} - \frac{10}{20} = -\frac{127}{20} = -6\frac{7}{20}[/tex]

Zadanie 6

Która suma jest dodatnia?   B

Która suma jest najmniejsza?   A

Która suma jest liczbą ujemną większą od -1?   D

Która suma nie jest ani dodatnia ani ujemna?      C

Obliczenia:

A. [tex]-6,4 + (-7\frac{5}{4}) = -\frac{32}{5} - 7\frac{4}{5} = -\frac{32}{5} - \frac{39}{5} = -\frac{71}{5} = -14\frac{1}{5}[/tex]

B. [tex]-8,9 + 9,8 = 0,9[/tex]

C. [tex]-6\frac{4}{5} + 6,8 = -\frac{34}{5} + \frac{34}{5} = 0[/tex]

D. [tex]-4\frac{5}{6} - (-4\frac{2}{3}) = -4\frac{5}{6} + 4\frac{2}{3} = -\frac{29}{6} + \frac{14}{3} = - \frac{29}{6} + \frac{28}{6} = -\frac{1}{6}[/tex]