[tex]Zadanie\\\\sin\alpha=\frac{3}{5}\\\\sin^2\alpha+cos^2\alpha=1\\\\1-cos^2\alpha= sin^2\alpha+cos^2\alpha-cos^2\alpha=sin^2\alpha=(\frac{3}{5})^2=\frac{9}{25}\\\\ Odp.\ D[/tex]