Odpowiedź:
C) A i B
Szczegółowe wyjaśnienie:
[tex]A = (-2,3), \ \ B = (1,-5), \ \ C = (4,4)\\\\a = \frac{y_2-y_1}{x_2-x_1}\\\\a_{AB} = \frac{-5-3}{1-(-2)} = \frac{-8}{1+2} = -\frac{8}{3}< 0\\\\a_{BC} = \frac{4-(-5)}{4-1} = \frac{4+5}{3} = \frac{9}{3} = 3 > 0\\\\a_{AC} = \frac{4-3}{4-(-2)} = \frac{1}{4+2} = \frac{1}{6} > 0\\\\Odp. \ c)[/tex]
