Odpowiedź:
[tex]B.\ \ (6^9)^3:(6^8)^2=6^{27}:6^{16}=6^{27-16}=6^{11}\\\\\\C.\ \ ((\frac{1}{2})^4)^5\cdot((\frac{1}{2})^4)^6=(\frac{1}{2})^{20}\cdot(\frac{1}{2})^{24}=(\frac{1}{2})^{20+24}=(\frac{1}{2})^{44}\\\\\\D.\ \ (0,7^4)^9:(0,7^5)^6=0,7^{36}:0,7^{30}=0,7^{36-30}=0,7^6[/tex]
