Odpowiedź:
[tex]a)\ \ \dfrac{3}{4}\cdot2\dfrac{2}{3}=\dfrac{\not3^1}{\not4_{1}}\cdot\dfrac{\not8^2}{\not3_{1}}=2\\\\\\b)\ \ 3\dfrac{1}{2}\cdot4\dfrac{2}{3}=\dfrac{7}{\not2_{1}}\cdot\dfrac{\not14^7}{3}=\dfrac{49}{3}=16\dfrac{1}{3}\\\\\\c)\ \ 1\dfrac{4}{7}\cdot2\dfrac{2}{3}\cdot2\dfrac{5}{8}=\dfrac{11}{7}\cdot\dfrac{\not8^1}{\not3_{1}}\cdot\dfrac{\not21^7}{\not8_{1}}=\dfrac{77}{7}=11[/tex]
[tex]d)\ \ \dfrac{2}{3}:\dfrac{5}{6}=\dfrac{2}{\not3_{1}}\cdot\dfrac{\not6^2}{5}=\dfrac{4}{5}\\\\\\e)\ \ 1\dfrac{1}{5}:\dfrac{24}{25}=\dfrac{\not6^1}{\not5_{1}}\cdot\dfrac{\not25^5}{\not24_{4}}=\dfrac{5}{4}=1\dfrac{1}{4}\\\\\\f)\ \ 1\dfrac{1}{6}:2\dfrac{4}{5}=\dfrac{7}{6}:\dfrac{14}{5}=\dfrac{\not7^1}{6}\cdot\dfrac{5}{\not14_{2}}=\dfrac{5}{12}[/tex]
