[tex]dane:\\v_1 = 108\frac{km}{h}\\t = 4 \ s\\v_2 = 72\frac{km}{h}\\szukane:\\a = ?\\\\Rozwiazanie\\\\a = \frac{\Delta v}{t}\\\\\Delta v = v_1 - v_2 = (108-72)\frac{km}{h} = 36\frac{km}{h} = 36\cdot\frac{1000 \ m}{3600 \ s} = 10\frac{m}{s}\\\\a = \frac{10\frac{m}{s}}{4 \ s}\\\\a = 2,5\frac{m}{s^{2}} \ - \ opoznienie[/tex]
