Odpowiedź :
kwadrat 1
a=4
kwadrat 2
P=35
a=5
kwadrat K
?
~~~
[tex] {4}^{2} + {x}^{2} = {5}^{2} \\ 16 + {x}^{2} = 35 \\ {x}^{2} = 35 - 16 \\ {x}^{2} = 19 \\ x = \sqrt{19} [/tex]
pole kwadratu K
[tex]p = { \sqrt{19} }^{2} = 19[/tex]
kwadrat 1
a=4
kwadrat 2
P=35
a=5
kwadrat K
?
~~~
[tex] {4}^{2} + {x}^{2} = {5}^{2} \\ 16 + {x}^{2} = 35 \\ {x}^{2} = 35 - 16 \\ {x}^{2} = 19 \\ x = \sqrt{19} [/tex]
pole kwadratu K
[tex]p = { \sqrt{19} }^{2} = 19[/tex]