[tex]dane:\\F_{w} = 9 \ kN = 9 \ 000 \ N\\a = 3\frac{m}{s^{2}} = 3\frac{N}{kg}\\szukane:\\m = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F_{w}}{m} \ \ \rightarrow \ \ m = \frac{F_{w}}{a}\\\\m = \frac{9000 \ N}{3\frac{N}{kg}}\\\\m = 3 \ 000 \ kg = 3 \ t[/tex]
Odp. Masa ciała wynosi 3000 kg (3 t).
