[tex]dane:\\l = 100 \ m\\s = 2,5 \ mm^{2}\\\rho =0,017\frac{\Omega\cdit mm^{2}}{m} \ - \ opor \ wlasciwy \ miedzi\\R = ?\\\\Rozwiazanie\\\\R = \rho\cdot\frac{l}{s}\\\\R = 0,017\frac{\Omega\cdot mm^{2}}{m} \cdot\frac{100 \ m}{2,5 \ mm^{2}}\\\\R = 0,68 \ \Omega[/tex]
