Odpowiedź :
Bazując na działaniach na potęgach:
a] [tex]4^{17}:(4^2\cdot4^3)^3=4^{17-3\cdot(2+3)}=4^{17-3\cdot5}=4^{17-15}=4^2=16\\[/tex]
b] [tex](3^4)^5:(3^2)^9\cdot3=3^{4\cdot5-2\cdot9+1}=3^{20-18+1}=3^3=27\\[/tex]
c] [tex]7^3\cdot(7^4)^5:(7^3)^7=7^{3+5\cdot4-7\cdot3}=7^{3+20-21}=7^2=49[/tex]
d] [tex]\frac{((\frac{1}{2})^4)^5:((\frac{1}{2})^2)^6 }{\frac{1}{2}\cdot((\frac{1}{2})^2)^3 }=(\frac{1}{2})^{5\cdot4-6\cdot2-(1+3\cdot2)}=(\frac{1}{2} )^{20-12-7}=\frac{1}{2}[/tex]