Odpowiedź:
[tex]a)\ \ -\sqrt{3}+6,021+4\frac{1}{6}+0,979+(-\frac{1}{6})+\sqrt{3}=6,021+0,979+4\frac{1}{6}-\frac{1}{6}=7+4=11\\\\\\b)\ \ 3,6\cdot(-\frac{1}{2})\cdot(-\frac{5}{6})\cdot4\cdot0,25=\frac{36}{10}\cdot\frac{5}{12}\cdot1=\frac{\not18^3}{\not5_{1}}\cdot\frac{\not5^1}{\not12_{2}}=\frac{3}{2}=1\frac{1}{2}[/tex]
