[tex]dane \ z \ wykresu:\\F = 3 \ N\\a = 6\frac{m}{s^{2}} = 6\frac{N}{kg}\\szukane:\\m = ?\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ \Rightarrow \ \ m = \frac{F}{a}\\\\m = \frac{3 \ N}{6\frac{N}{kg}} = 0,5 \ kg[/tex]
Odp. Masa tego ciała m = 0,5 kg.
