Odpowiedź:
[tex]a)\ \ (-2)^2\cdot(-2)^3=4\cdot(-8)=-32\\\\\\b)\ \ (1\frac{1}{6})^3:(\frac{7}{6})^3=(\frac{7}{6})^3:(\frac{7}{6})^3=1\\\\\\c)\ \ \sqrt[3]{1\frac{1}{3}}:\sqrt[3]{4,5}=\sqrt[3]{1\frac{1}{3}:4,5}=\sqrt[3]{\frac{4}{3}:\frac{45}{10}}=\sqrt[3]{\frac{4}{3}:\frac{9}{2}}=\sqrt[3]{\frac{4}{3}\cdot\frac{2}{9}}=\sqrt[3]{\frac{8}{27}}=\frac{2}{3}\\\\\\d)\ \ (2,5\cdot0,04)^2=0,1^2=(\frac{1}{10})^2=\frac{1}{100}=0,01[/tex]
[tex]e)\ \ (0,002)^3\cdot(-0,5)^3=-(0,002\cdot0,5)^3=-0,001^3=-(\frac{1}{1000})^3=-\frac{1}{1000000000}\\\\\\f)\ \ \left(\sqrt{2,4}\cdot\sqrt{\frac{5}{12}}\right)^6=\left(\sqrt{2,4\cdot\frac{5}{12}}\right)^6=\left(\sqrt{\frac{24}{10}\cdot\frac{5}{12}}\right)^6=\left(\sqrt{\frac{\not12^1}{\not5_{1}}\cdot\frac{\not5^1}{\not12_{1}}}\right)^6=1^6=1[/tex]
