[tex]dane:\\m = 1 \ t = 1000 \ kg\\v_{o} = 0\\t = 0,5 \ min = 30 \ s\\v = 45\frac{m}{s}\\szukane:\\F = ?\\\\Rozwiazanie\\\\a = \frac{\Delta v}{t} = \frac{v-v_{o}}{t} = \frac{v}{t} = \frac{45\frac{m}{s}}{30 \ s} = 1,5\frac{m}{s^{2}}\\\\Z \ II \ zasady \ dynamiki\\\\F = m\cdot a\\\\F = 1000 \ kg\cdot1,5\frac{m}{s^{2}}\\\\F = 1 \ 500 \ N = 1,5 \ kN\\\\(1 \ kN = 1000 \ N)[/tex]
Odp. Musi działać siła F = 1,5 kN.
