Odpowiedź :
Odpowiedź:
[tex]6.a)2 \frac{3}{5} + 1 \frac{3}{4} = 2 \frac{12}{20} + 1 \frac{15}{20} = 3 \frac{27}{20} = 4 \frac{7}{20} \\ b)4 \frac{2}{3} - 2 \frac{7}{8} = 4 \frac{16}{24} - 2 \frac{21}{24} = 1 \frac{19}{24} [/tex]
[tex]7. \: 7 \frac{1}{12} - x = 2 \frac{1}{3} \\ - x = 2 \frac{1}{3} - 7 \frac{1}{12} \\ - x = 2 \frac{4}{12} - 7 \frac{1}{12} \\ - x = - 4 \frac{9}{12} \\ x = 4 \frac{3}{4} [/tex]
Zadanie 6
A) 2 3/5 + 1 3/4 = 2 12/20 + 1 15/20 = 3 27/20 = 4 7/20
B) 4 2/3 - 2 7/8 = 4 16/24 - 2 21/24 = 3 40/24 - 2 21/24 = 1 19/24
Zadanie 7
7 1/12 - x = 2 1/3
7 1/12 - x = 2 4/12 |-2 4/12
4 9/12 = x
x = 4 3/4
Pozdrawiam~Haruqe