Odpowiedź:
a)
[tex] x \sqrt{9} - {2}^{2} = x \sqrt{25 +} + \sqrt{4} \\ x \times 3 - 4 = 5x + 2 \\ 3x - 4 = 5x + 2 \\ 3x - 5x = 2 + 4 \\ - 2x = 6 \\ x = - 3[/tex]
b)
[tex] \sqrt{4} (x + {4}^{0} = \sqrt{16} - x \\ 2(x + 1) = - 4 - x \\ 2x + 2 = - 4 - x \\ 2x + x = - 4 - 2 \\ 3x = - 6 \\ x = - 2 [/tex]
c)
[tex] \frac{x}{ \sqrt{36} } + ( { \sqrt{2} })^{2} = \frac{x + {3}^{0} }{ \sqrt{9} } - x \\ \frac{x}{6} + 2 = \frac{x + 1}{3} - x \\ x + 12 = 2(x + 1) - 6x \\ x + 12 = 2x + 2 - 6x \\ x + 12 = - 4x + 2 \\ x + 4x = 2 - 12 \\ 5x = - 10 \\ x = - 2[/tex]
d) nie wiem
