[tex]2x^2+2x-15<0\\\Delta = 2^2 -4\cdot2\cdot(-15)=4+120=124\\\sqrt{\Delta} = \sqrt{124}=2\sqrt{31}\\\\x_1 = \frac{-b-\sqrt{\Delta}}{2a}=\frac{-2-2\sqrt{31}}{4}=\frac{-1-\sqrt{31}}{2}\\x_2 = \frac{-b+\sqrt{\Delta}}{2a}=\frac{-2+2\sqrt{31}}{4}=\frac{-1+ \sqrt{31}}{2}\\x\in(\frac{-1-\sqrt{31}}{2}, \frac{-1+ \sqrt{31}}{2})[/tex]
Liczby całkowite:
[tex]x = \{-3,-2,-1,0,1,2\}[/tex]
