pls pomocy do jutra mam odesłać

[tex]a)(6x-3)-(4x+5)=6x-3-4x-5=(6x-4x)+(-3-5)=2x-8\\b)-3x-(5-x)+3=-3x-5+x+3=(-3x+x)+(-5+3)=-2x-2\\c)(4a-6)+(4a+6)=4a-6+4a+6=(4a+4a)+(-6+6)=8a+0=8a[/tex]

Zad.7

[tex]a)a(6+a^2)-5(2a-a^2)+2a(a^2-1)=6a+a^3-10a+5a^2+2a^3-2a=\\=(a^3+2a^3)+5a^2+(6a-10a-2a)=3a^3+5a^2-6a\\\\b)x^2(yx-y)-y(xy^2-x^2)=x^3y-x^2y-xy^3+x^2y=\\=x^3y+(-x^2y+x^2y)-xy^3=x^3y-xy^3\\\\c)-\frac{2}{3}a(-3b^2-6ab)=-2ab^2+4a^2b=4a^2b-2ab^2[/tex]

Benek9732viz Benek9732viz · Answer 2

Odpowiedź:

Szczegółowe wyjaśnienie:

Zad. 1

C

Zad. 2

a) - 4a + 4 + 9a - 2a = 3a + 4

b) x - 3y - 4x + 3y - 2y = -3x - 2y

c) 2x² + 2y - 5x -3y - x² = x²- 5x - y

Zad. 3

a) 7a - [tex]\frac{1}{3}a[/tex] dla a = 9

7* 9 - [tex]\frac{1}{3}[/tex] * 9 = 63 - 3 = 60

b) 3b² + 2b dla b = - 3

3* (-3)² + 2 * (-3) = 3 * 9 - 6 = 27 - 6 = 21

c) (3x + 4y)(6 - x) dla x = 2 i y = -3

(3 * 2 + 4* (-3)) * (6 - 2) = (6 -12) * 4 = - 6 * 4 = -24

Zad. 4

3a - 4b + 3a - 2b = 6a - 6b

6a - 6b - 2a - 3b = 4a - 9b

Zad. 5

(15a - 10) * 2 = 30a - 20

(30a - 20) : 5 = 6a - 4

Zad. 6

(6x - 3) - (4x + 5) = 6x -3 - 4x - 5 = 2x - 8

- 3x - (5 - x) + 3 = - 3x - 5 + x + 3 = -2x - 2

Zad. 7

a) a(6 + a²) - 5(2a - a²) + 2a(a² - 1) = 6a + a³ - 10a + 5a² + 2a³ - 2a = 3a³ - 5a²- 6a

b) x²(yx - y) - y(xy² - x²) = x³y - x²y - xy³ + x²y = x³y - xy³

c) [tex]-\frac{2}{3}a[/tex] (-3b² - 6ab) =2ab² + 4a²b

Odpowiedź :

Zad.1

Zad.2

Zad.3

[tex]a)7a-\frac{1}{3}x~~dla~~a=9\\7*9-\frac{1}{3}*9=63-3=60\\\\b)3b^2+2b~~dla~~b=-3\\3*(-3)^2+2*(-3)=3*9-6=27-6=21\\\\c)(3x+4y)(6-x)~~dla~~x=2~~i~~y=-3\\(3*2+4*(-3))*(6-2)=(6-12)*4=-6*4=-24[/tex]

Zad.4

Zad.5

Zad.6

Zad.7

Viz Inne Pytanie

[tex]a)7a-\frac{1}{3}xdlaa=9\\79-\frac{1}{3}9=63-3=60\\\\b)3b^2+2bdlab=-3\\3(-3)^2+2(-3)=39-6=27-6=21\\\\c)(3x+4y)(6-x)dlax=2iy=-3\\(32+4(-3))(6-2)=(6-12)4=-64=-24[/tex]