[tex]e = 60 \ mm\\f = 80 \ mm\\h = 48 \ mm\\a = ?[/tex]
[tex]P = a\cdot h\\oraz\\P = \frac{e\cdot f}{2}\\\\a\cdot h = \frac{e\cdot f}{2} \ \ /\cdot2\\\\2ah = ef \ \ /:2h\\\\a = \frac{ef}{2h}\\\\a = \frac{60mm\cdot80mm}{2\cdot48 mm} = \frac{48000 \ mm^{2}}{96 \ mm}\\\\a = 50 \ mm[/tex]
Odp. Długość boku tego rombu a = 50 mm.
