rozwiąż równania
DAJE NAJ!!

[tex]a)\\\frac{x}{6}-3 = 4\\\\\frac{x}{6} = 4+3\\\\\frac{x}{6} = 7 \ \ /\cdot6\\\\x = 42[/tex]
[tex]b)\\\frac{x}{5} + 8 = 20\\\\\frac{x}{5} = 20-8\\\\\frac{x}{5} = 12 \ \ /\cdot5\\\\x = 60[/tex]