--Odpowiedź: a) x = [tex]\frac{6}{7}[/tex]
b) x = 1
c) x [tex]\leq[/tex] [tex]\frac{1}{3}[/tex]
d) x [tex]\geq[/tex] / [tex]\frac{8}{11}[/tex]
Szczegółowe wyjaśnienie:
a)6 x (^2) -3x -8x +4 = -6x(^2) - 6x + 2x - 2 = -11x +4 = -4x -2 = -7x = -6 = [tex]\frac{6}{7}[/tex]
b) 18x(^2) - 9x +2x - 1 = 1 - 3x - 6x + 18x (^2) = -7x - 1 = 1 - 9x = 2x = 2 = x = 1
c)9x(^2) - (9 - 18x + 8x (^2) ) [tex]\leq[/tex] x (^2) - 9x = x (^2) - 9 + 18x [tex]\leq[/tex] - 9x = 27x [tex]\leq[/tex] 9 = x [tex]\leq[/tex] [tex]\frac{1}{3}[/tex]
d) 2x (^2) + x + 3x + [tex]\frac{3}{2}[/tex] [tex]\geq[/tex] / 2x(^2) -2x + [tex]\frac{1}{2}[/tex] * - [tex]\frac{1}{2}[/tex] + 6 = 4x = [tex]\frac{3}{2}[/tex] [tex]\geq[/tex] / - [tex]\frac{3}{2}[/tex] x + [tex]\frac{11}{2}[/tex] = 11x [tex]\geq[/tex] / 8 = x [tex]\geq[/tex] / [tex]\frac{8}{11}[/tex]
Nie ma za co :-)
