[tex]dane:\\v_{o} = 0\\v = 25\frac{m}{s}\\g = 10\frac{m}{s^{2}}\\szukane:\\h = ?\\\\Rozwiazanie\\\\h = \frac{1}{2}gt^{2}}\\\\\\v = g\cdot t \ \ /:g\\\\t = \frac{v}{g} = \frac{25\frac{m}{s}}{10\frac{m}{s^{2}}} = 2,5 \ s\\\\\\h = \frac{1}{2}\cdot10\frac{m}{s^{2}}\cdot(2,5 \ s)^{2}\\\\h = 31,25 \ m[/tex]
Odp. Ciało spadało z wysokoci h = 31,25 m.
