[tex]x \sqrt{9} + 2(x - 1) + 3(x + 5) = \frac{3x + 5}{2} \\ 3x + 2x - 2 + 3x + 15 = \frac{3x + 5}{2} \\ 8x + 13 = \frac{3x + 5}{2} \: \: | \times 2 \\ 16x + 26 = 3x + 5 \: \: | - 3x \\ 13x + 26 = 5 \: \: | - 26 \\ 13x = - 21 \: \: | \div 13 \\ x = - 1 \frac{8}{13} [/tex]