Proszę o pomoc z matematyki
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Odpowiedź:
[tex]3(5-2x)\leq -2(2x-1)\\15-6x\leq -4x+2\\-6x+4x\leq 2-15\\-2x\leq -13\\x\geq \frac{-13}{-2} \\x\geq 6,5[/tex]
Zatem: x ∈ <6,5 ; +∞)
Odp. A
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