a)
[tex] \sqrt{ {3}^{2} + {4}^{2} } = \\ = \sqrt{9 + 16} = \\ = \sqrt{25} = \\ = 5[/tex]
b)
[tex] \sqrt{9 \sqrt{16} } = \\ = \sqrt{9 \times 4} = \\ = \sqrt{36} = \\ = 6[/tex]
c)
[tex] \sqrt{16} + \sqrt{36} = \\ = 4 + 6 = \\ = 10[/tex]
d)
[tex] \sqrt{ \frac{98}{128} } = \sqrt{ \frac{49}{64} } = \frac{ \sqrt{49} }{ \sqrt{64} } = \frac{7}{8} [/tex]
