[tex]Zadanie\ 2\\\\x=-2;\ y=-\frac{1}{4}\\\\ 2x^{2} -y+x^{3}\\\\2\cdot(-2)^{2}-(- \frac{1}{4})+(-2)^{3}=2\cdot4+\frac{1}{4}-8=8+\frac{1}{4}-8=\frac{1}{4}[/tex]
Zadanie 3
a)
(2x³ + 3x - 7) + (4x³ - 7x - 9) = 2x³ + 3x - 7 + 4x³ - 7x - 9 = 6x³ - 4x - 16
b)
(2xy + 4y² - 5) - (6xy + 8y² - 10) = 2xy + 4y² - 5 - 6xy - 8y ² + 10 = -4y² -4xy + 5
(2xy + 4y² - 5) - (6xy + 6y² - 10) = 2xy + 4y² - 5 - 6xy - 6y ² + 10 = -2y² -4xy + 5
Zadanie 4
3(a - 3b) - 4(2b - 4a) = 3a - 9b - 8b + 16a = 19a - 17b
