Odpowiedź:
a)[H+] =10 ^-3 mol/dm3
pH =-log[H+}]
pH= -log (10^-3)
pH =3
b)[H+} = 0,1 mol/dm3
pH = - log( 10^-1)
pH=1
c)[OH] = 1mol /dm3
p[OH] =-log [10^1]
p[OH] = 10
