[tex]a)\\\\ x(x + 3)^2(x^2-4) \geq 0 \\\\x(x + 3)^2(x-2)(x+2) \geq 0\\\\obliczamy\ miejsca\ zerowe :\\\\x(x + 3)^2(x^2-4) =0\\\\x=0\ \ lub\ \ (x + 3)^2=0\ \ lub\ \ x-2=0\ \ lub\ \ x+2=00\\\\x=0\ \ lub\ \ x =-3 \ \ lub\ \ x=2\ \ lub\ \ x=-2\\\\x=-3\ \ lub\ \ x\in <-2,0> \cup (2,\infty )[/tex]
[tex]b )\\\\ -x^3 + x^2 + x-1 < 0\ \ |*(-1)\\\\x^3 - x^2 - x+1 >0\\\\x^2(x-1)-(x-1)>0\\\\(x^2-1)(x-1)>0\\\\(x+1)(x-1)(x-1)>0\\\\(x+1)(x-1)^2>0 \\\\x\in(1,\infty )[/tex]
