Odpowiedź:
Zad 2.
1.
[tex]4xy+A=xy-x\\A=xy-4xy-x\\A=-3xy-x[/tex]
2.
[tex]-mn+A=1\\A=1+mn[/tex]
3.
[tex]3x^2-3x+A=-x\\A=-x+3x-3x^2\\A=2x-3x^2[/tex]
4.
[tex]pq-q+A=2pg\\A=2pq-pg+q\\A=pg+q[/tex]
Zad 3.
a) [tex](4x-2)-(-5x+3) = 4x-2+5x-3 = 9x-5[/tex]
b) [tex]-(y^2+5y-6)-(2y^2-y+8) = -y^2-5y+6-2y^2+y-8 = -3y^2-4y-2[/tex]
c)
[tex](-5x^2-ax+a^2)+(-3x^2+2ax-3a^2) = -5x^2-ax+a^2-3x^2+2ax-3a^2 = -8x^2+ax-2a^2[/tex]
d) [tex](2xy-5x^2y)-(-10xy+2x^2y) = 2xy-5x^2y+10xy-2x^2y=12xy-7x^2y[/tex]
e) [tex]-(-12abc-4a^2bc)+(abc-a^2bc)= 12abc+4a^2bc+abc-a^2bc = 13abc +3a^2bc[/tex]
f)
[tex](0,4ab-0,5bc+0,1cd)-(-0,3ab+2,5bc-cd) = 0,4ab-0,5bc+0,1cd +0,3ab-2,5bc+cd = 0,7ab-3bc+1,1cd[/tex]
g)
[tex]-(2a^2-4ab-b^2)+(-a^2+3b^2-5ab)-(8a^2-ab+7b^2)=-2a^2+4ab+b^2-a^2+3b^2-5ab-8a^2+ab-7b^2 = -9a^2-3b^2[/tex]
h) [tex]-8b^2+[6b^2-(2a-a^2)-3a] = -8b^2 + 6b^2-2a+a^2-3a = -2b^2-5a+a^2[/tex]
i) [tex]4(-3x-5) = -12x-20[/tex]
j) [tex]-8(5m+2) = -40m-16[/tex]
k) [tex]-2(5t+8) = -10t-16[/tex]
l) [tex]-3(-2a-7) = 6a+21[/tex]
m) [tex]5a(-2ab-4a+2b) = -10ab-20a+10b[/tex]
n) [tex]-6ab(3a+4b+2) = -18a^2b-24ab^2-12ab[/tex]
Szczegółowe wyjaśnienie:
