[tex]Zadanie\ 9\\\\a)\\\\\sqrt{12}+5\sqrt{3}= \sqrt{4\cdot3}+5\sqrt{3}= 2\sqrt{3}+ 5\sqrt{3}=7\sqrt{3}\\\\b)\\\\2\sqrt{48}+2\sqrt{3}= 2\sqrt{16\cdot3}+2\sqrt{3}= 8\sqrt{3}+ 2\sqrt{3} = 10\sqrt{3} \\\\c)\\\\3\sqrt{20}+\sqrt{5}= 3\sqrt{4\cdot5}+ \sqrt{5}=6\sqrt{5}+ \sqrt{5}= 7\sqrt{5}[/tex]
