1.
[tex]\dfrac{a+b}{2}=10\\\\a+b=20\\\\\\\dfrac{a+b+10}{3}=\dfrac{20+10}{3}=\dfrac{30}{3}=10[/tex]
2.
Niech [tex]a[/tex] oznacza długość boku.
Z twierdzenia Pitagorasa:
[tex]a^2=\left(\dfrac{1}{2}p\right)^2+\left(\dfrac{1}{2}q\right)^2\\\\a^2=\dfrac{p^2}{4}+\dfrac{q^2}{4}\\\\a^2=\dfrac{p^2+q^2}{4}\\\\a=\sqrt{\dfrac{p^2+q^2}{4}}\\\\a=\dfrac{\sqrt{p^2+q^2}}{\sqrt4}\\\\a=\dfrac{\sqrt{p^2+q^2}}{2}[/tex]