Odpowiedź:
[tex]\begin{cases}\frac{x}{12}+\frac{y}{8}=1\ \ /*24\\\frac{x-2}{4}-\frac{y-6}{2}=2\end{cases}\\\\\\\begin{cases}2x+3y=24\\x-2-2(y-6)=8\end{cases}\\\\\\\begin{cases}2x+3y=24\\x-2-2y+12=8\end{cases}\\\\\\\begin{cases}2x+3y=24\\x-2y=8+2-12\end{cases}\\\\\\\begin{cases}2x+3y=24\\x-2y=-2\ \ /*(-2)\end{cases}\\\\\\+\begin{cases}2x+3y=24\\-2x+4y=4\end{cases}\\---------\\7y=28\ \ /:7\\y=4\\\\\\x-2\cdot4=-2\\\\x-8=-2\\\\x=-2+8\\\\x=6\\\\\begin{cases}x=6\\y=4\end{cases}[/tex]
