[tex]dane:\\m = 45 \ kg\\S = 0,004 \ m^{2}\\g = 10\frac{N}{kg}\\szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\F = m\cdot g\\\\p = \frac{m\cdot g}{S}\\\\p = \frac{45 \ kg\cdot10\frac{N}{kg}}{0,004 \ m^{2}} = 112 \ 500 \ Pa = 112,5 \ kPa\\\\(1 \ kPa = 1000 \ Pa)[/tex]
