Odpowiedź:
a) 2p^2-4/3p-1/2p^2-1/3p=3/2p^2-5/3p
b) -5/4x-5/2y+9/4x-3/2y=x-4y
c) [tex]\frac{5m-2}{10}[/tex]*1/2+[tex]\frac{5m+4}{10}[/tex]*1/4= [tex]\frac{5m-2}{20}[/tex]+[tex]\frac{x5m+4}{40}[/tex]= [tex]\frac{2(5m-2)+5m+4}{40}[/tex]=[tex]\frac{10m-4+5m+4}{40}[/tex]=15m/40=3m/8
d) [tex]\frac{8a+9b}{12} *\frac{1}{6} -\frac{1/3a+1/2b}{4}[/tex]=[tex]\frac{8a+9b}{72} -\frac{\frac{2a+3b}{6} }{4} =\frac{8a+9b}{72}-\frac{2a+3b}{24}[/tex][tex]= \frac{8a+9b-3(2a+3b)}{72}=\frac{8a+9b-6a-9b}{72} = \frac{2a}{72} =\frac{a}{36}[/tex]
e) [tex]\frac{2}{3} u+\frac{1}{2} -\frac{1/2u+3/4}{3} =\frac{2}{3} u+\frac{1}{2} -\frac{\frac{2u+3}{4} }{3} =\frac{8u+6-(2u+3)}{12} =\frac{8u+6-2u-3}{12} =\frac{6u+3}{12} =\frac{2u+1}{4}[/tex]
Szczegółowe wyjaśnienie:
