Odpowiedź:
[tex]a)\ \ 9^4\cdot3=(3^2)^4\cdot3=3^8\cdot3=3^{8+1}=3^9\\\\b)\ \ \frac{2^1^0}{16}=\frac{2^{10}}{2^4}=2^{10-4}=2^6\\\\c)\ \ (7^2)^4=7^{2\cdot4}=7^8\\\\d)\ \ (\frac{1}{4})^8\cdot0,25^2=(\frac{1}{4})^8\cdot(\frac{1}{4})^2=(\frac{1}{4})^{8+2}=(\frac{1}{4})^{10}\\\\e)\ \ 7^6:49=7^6:7^2=7^{6-2}=7^4\\\\f)\ \ 15^7:3^7=(15:3)^7=5^7\\\\g)\ \ 4^3\cdot(4^2)^3=4^3\cdot4^6=4^{3+6}=4^9\\\\h)\ \ 3^8\cdot27:3^5=3^8\cdot3^3:3^5=3^{8+3-5}=3^6[/tex]
