[tex] \frac{2}{9} \div {( \frac{2}{3}) }^{2} + 1 \frac{5}{8} = \frac{2}{9} \div \frac{4}{9} + \frac{13}{8} = \frac{2}{9} \times \frac{9}{4} + \frac{13}{8} = \frac{1}{2} + \frac{13}{8} = \frac{4}{8} + \frac{13}{8} = \frac{17}{8} = 2 \frac{1}{8} [/tex]
mam nadzieje ze pomoglam ❤
