Odpowiedź:
[tex]a)\\\\3(x-4)-(3+6x)\geq 4(x-1)\\\\3x-12-3-6x\geq 4x-4\\\\-3x-15\geq 4x-4\\\\-3x-4x\geq -4+15\\\\-7x\geq 11\ \ /:(-7)\\\\x\leq -\frac{11}{7}\\\\x\leq -1\frac{4}{7}\\\\x\in(-\infty,-1\frac{4}{7}\rangle\\\\\\b)\\\\\frac{x}{5}-\frac{x-2}{10}<1\ \ /*10\\\\2x-(x-2)<10\\\\2x-x+2<10\\\\x<10-2\\\\x<8\\\\x\in(-\infty,8)[/tex]
