Hej!
[tex](x-5)(3x+18)(x^2-7)=0\\\\x-5=0 \ \vee \ 3x+18=0 \ \vee \ x^2-7=0\\\\x=5 \ \vee \ 3x=-18 \ \vee \ (x+\sqrt7)(x-\sqrt7)=0\\\\x=5 \ \vee \ x=-6 \ \vee \ x=-\sqrt7 \ \vee \ x=\sqrt7\\\\x\in\{-6; -\sqrt7;\sqrt7;5\}[/tex]
Pozdrawiam! - Julka
