Szczegółowe wyjaśnienie:
a) [tex]25^{\frac{1}{2} }+8^{\frac{1}{3} } =\sqrt{25} +\sqrt[3]{8} =5+2=7[/tex]
b) [tex]32^{\frac{1}{5} } +8^{\frac{1}{4} } =\sqrt[5]{32} +\sqrt[4]{8} =2+\sqrt[4]{8}[/tex]
c) [tex]4^{-\frac{1}{2} } +8^{-\frac{1}{3} } =(\frac{1}{4}) ^{\frac{1}{2} } +(\frac{1}{8}) ^{\frac{1}{3} } =\frac{\sqrt{1} }{\sqrt{4} } +\frac{\sqrt[3]{1} }{\sqrt[3]{8} } =\frac{1}{2}+\frac{1}{2} =1[/tex]
d) [tex](\frac{9}{16})^{-\frac{1}{2}} +(\frac{27}{64})^{-\frac{1}{3}} =(\frac{16}{9}) ^{\frac{1}{2} } +(\frac{64}{27} )^{\frac{1}{3} } =\frac{\sqrt{16} }{\sqrt{9}} +\frac{\sqrt[3]{64} }{\sqrt[3]{27} } =\frac{4}{3} +\frac{4}{3} =\frac{8}{3} =6\frac{2}{3}[/tex]
